If A is currently 12 years old and is to be twice as old as B in future years, what will be B's age at that time?

To determine the age of B when A is twice as old, we first need to express the relationship between their ages. Currently, A is 12 years old. Let's denote the current age of B as "b."

In the future, we can specify a number of years, say "x," that passes. At that time, A will be 12 + x years old, and B will be b + x years old. The condition given in the question is that A will then be twice B's age, which can be expressed mathematically as:

12 + x = 2(b + x)

This equation represents the relationship we need to solve. Simplifying it leads to:

12 + x = 2b + 2x

12 = 2b + x

Next, we can express x in terms of b:

x = 12 - 2b

Now, in order for 'x' to remain a non-negative number (since time cannot go backward), we need b to be less than or equal to 6, which suggests that B is currently younger than A.

Testing the possible ages for B:

If B is 6 years old now:

• In x years, substituting b