A is currently 12 years old and three times as old as his brother B. How old will A be to be twice as old as B?

To determine the age at which A will be twice as old as B, let's first establish the current ages of both individuals. A is currently 12 years old, and since A is three times as old as B, we can find B's current age. If A is three times B's age, we can set up the equation:

A = 3B

12 = 3B

Solving this gives us B's current age:

B = 12 / 3

B = 4 years old.

Now, we are looking for a point in the future where A will be twice as old as B. Let’s denote the number of years in the future as "x." In "x" years, A's age will be (12 + x) and B's age will be (4 + x). We need to find x when A is twice as old as B:

12 + x = 2(4 + x).

Expanding this, we have:

12 + x = 8 + 2x.

To isolate x, we rearrange the equation:

12 - 8 = 2x - x,

4 = x.

Thus, in 4 years, A will be 12 +